Match the corresponding entries of Column-I w | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The magnification $m$ for a mirror is given by $m = -v/u$. $1$. $m = -2$: Negative sign indicates a real and inverted image. Since $|m| > 1$,it is

Vedclass · Accepted Answer

$1-(b, c), 2-(b, c), 3-(b, d), 4-(a, d)$

Vedclass · Answer

(A) The magnification $m$ for a mirror is given by $m = -v/u$. $1$. $m = -2$: Negative sign indicates a real and inverted image. Since $|m| > 1$,it is a concave mirror. So,$(b, c)$. $2$. $m = -1/2$: Negative sign indicates a real and inverted image. Since $|m| $3$. $m = +2$: Positive sign indicates a virtual and erect image. Since $|m| > 1$,it is a concave mirror. So,$(b, d)$. $4$. $m = +1/2$: Positive sign indicates a virtual and erect image. Since $|m| < 1$,it is a convex mirror. So,$(a, d)$.

Match the corresponding entries of Column-$I$ with Column-$II$. (Where $m$ is the magnification produced by the mirror)

Similar Questions

The plates of a parallel plate capacitor are charged up to $100 \, V$. $A$ $2 \, mm$ thick plate is inserted between the plates. To maintain the same potential difference,the distance between the capacitor plates is increased by $1.6 \, mm$. The dielectric constant of the plate is:

In the figure shown,the potential energy $(U)$ of a particle is plotted against its position $x$ from the origin. The particle at:

The following series $L-C-R$ circuit,when driven by an emf source of angular frequency $70 \text{ krad/s}$,the circuit effectively behaves like:

The eccentricity of the conic $36x^2 + 144y^2 - 36x - 96y - 119 = 0$ is

If $x^2+px+1$ is a factor of the expression $ax^3+bx+c$,then

Vedclass Test Series

Exam Paper Generator

Online Exam Module